Integrand size = 33, antiderivative size = 48 \[ \int \frac {a+b x+c x^2}{x^2 \sqrt {1-d x} \sqrt {1+d x}} \, dx=-\frac {a \sqrt {1-d^2 x^2}}{x}+\frac {c \arcsin (d x)}{d}-b \text {arctanh}\left (\sqrt {1-d^2 x^2}\right ) \]
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Time = 0.11 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.212, Rules used = {1623, 1821, 858, 222, 272, 65, 214} \[ \int \frac {a+b x+c x^2}{x^2 \sqrt {1-d x} \sqrt {1+d x}} \, dx=-\frac {a \sqrt {1-d^2 x^2}}{x}+\frac {c \arcsin (d x)}{d}-b \text {arctanh}\left (\sqrt {1-d^2 x^2}\right ) \]
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Rule 65
Rule 214
Rule 222
Rule 272
Rule 858
Rule 1623
Rule 1821
Rubi steps \begin{align*} \text {integral}& = \int \frac {a+b x+c x^2}{x^2 \sqrt {1-d^2 x^2}} \, dx \\ & = -\frac {a \sqrt {1-d^2 x^2}}{x}-\int \frac {-b-c x}{x \sqrt {1-d^2 x^2}} \, dx \\ & = -\frac {a \sqrt {1-d^2 x^2}}{x}+b \int \frac {1}{x \sqrt {1-d^2 x^2}} \, dx+c \int \frac {1}{\sqrt {1-d^2 x^2}} \, dx \\ & = -\frac {a \sqrt {1-d^2 x^2}}{x}+\frac {c \sin ^{-1}(d x)}{d}+\frac {1}{2} b \text {Subst}\left (\int \frac {1}{x \sqrt {1-d^2 x}} \, dx,x,x^2\right ) \\ & = -\frac {a \sqrt {1-d^2 x^2}}{x}+\frac {c \sin ^{-1}(d x)}{d}-\frac {b \text {Subst}\left (\int \frac {1}{\frac {1}{d^2}-\frac {x^2}{d^2}} \, dx,x,\sqrt {1-d^2 x^2}\right )}{d^2} \\ & = -\frac {a \sqrt {1-d^2 x^2}}{x}+\frac {c \sin ^{-1}(d x)}{d}-b \tanh ^{-1}\left (\sqrt {1-d^2 x^2}\right ) \\ \end{align*}
Time = 0.21 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.52 \[ \int \frac {a+b x+c x^2}{x^2 \sqrt {1-d x} \sqrt {1+d x}} \, dx=-\frac {a \sqrt {1-d^2 x^2}}{x}+\frac {2 c \arctan \left (\frac {d x}{-1+\sqrt {1-d^2 x^2}}\right )}{d}-b \log (x)+b \log \left (-1+\sqrt {1-d^2 x^2}\right ) \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 1.60 (sec) , antiderivative size = 97, normalized size of antiderivative = 2.02
method | result | size |
default | \(\frac {\left (-\operatorname {arctanh}\left (\frac {1}{\sqrt {-d^{2} x^{2}+1}}\right ) \operatorname {csgn}\left (d \right ) d b x -\sqrt {-d^{2} x^{2}+1}\, \operatorname {csgn}\left (d \right ) d a +\arctan \left (\frac {\operatorname {csgn}\left (d \right ) d x}{\sqrt {-d^{2} x^{2}+1}}\right ) c x \right ) \sqrt {-d x +1}\, \sqrt {d x +1}\, \operatorname {csgn}\left (d \right )}{\sqrt {-d^{2} x^{2}+1}\, x d}\) | \(97\) |
risch | \(\frac {a \sqrt {d x +1}\, \left (d x -1\right ) \sqrt {\left (-d x +1\right ) \left (d x +1\right )}}{x \sqrt {-\left (d x +1\right ) \left (d x -1\right )}\, \sqrt {-d x +1}}+\frac {\left (\frac {c \arctan \left (\frac {\sqrt {d^{2}}\, x}{\sqrt {-d^{2} x^{2}+1}}\right )}{\sqrt {d^{2}}}-b \,\operatorname {arctanh}\left (\frac {1}{\sqrt {-d^{2} x^{2}+1}}\right )\right ) \sqrt {\left (-d x +1\right ) \left (d x +1\right )}}{\sqrt {-d x +1}\, \sqrt {d x +1}}\) | \(129\) |
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Time = 0.24 (sec) , antiderivative size = 84, normalized size of antiderivative = 1.75 \[ \int \frac {a+b x+c x^2}{x^2 \sqrt {1-d x} \sqrt {1+d x}} \, dx=\frac {b d x \log \left (\frac {\sqrt {d x + 1} \sqrt {-d x + 1} - 1}{x}\right ) - \sqrt {d x + 1} \sqrt {-d x + 1} a d - 2 \, c x \arctan \left (\frac {\sqrt {d x + 1} \sqrt {-d x + 1} - 1}{d x}\right )}{d x} \]
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Result contains complex when optimal does not.
Time = 28.14 (sec) , antiderivative size = 221, normalized size of antiderivative = 4.60 \[ \int \frac {a+b x+c x^2}{x^2 \sqrt {1-d x} \sqrt {1+d x}} \, dx=\frac {i a d {G_{6, 6}^{5, 3}\left (\begin {matrix} \frac {5}{4}, \frac {7}{4}, 1 & \frac {3}{2}, \frac {3}{2}, 2 \\1, \frac {5}{4}, \frac {3}{2}, \frac {7}{4}, 2 & 0 \end {matrix} \middle | {\frac {1}{d^{2} x^{2}}} \right )}}{4 \pi ^{\frac {3}{2}}} + \frac {a d {G_{6, 6}^{2, 6}\left (\begin {matrix} \frac {1}{2}, \frac {3}{4}, 1, \frac {5}{4}, \frac {3}{2}, 1 & \\\frac {3}{4}, \frac {5}{4} & \frac {1}{2}, 1, 1, 0 \end {matrix} \middle | {\frac {e^{- 2 i \pi }}{d^{2} x^{2}}} \right )}}{4 \pi ^{\frac {3}{2}}} + \frac {i b {G_{6, 6}^{5, 3}\left (\begin {matrix} \frac {3}{4}, \frac {5}{4}, 1 & 1, 1, \frac {3}{2} \\\frac {1}{2}, \frac {3}{4}, 1, \frac {5}{4}, \frac {3}{2} & 0 \end {matrix} \middle | {\frac {1}{d^{2} x^{2}}} \right )}}{4 \pi ^{\frac {3}{2}}} - \frac {b {G_{6, 6}^{2, 6}\left (\begin {matrix} 0, \frac {1}{4}, \frac {1}{2}, \frac {3}{4}, 1, 1 & \\\frac {1}{4}, \frac {3}{4} & 0, \frac {1}{2}, \frac {1}{2}, 0 \end {matrix} \middle | {\frac {e^{- 2 i \pi }}{d^{2} x^{2}}} \right )}}{4 \pi ^{\frac {3}{2}}} - \frac {i c {G_{6, 6}^{6, 2}\left (\begin {matrix} \frac {1}{4}, \frac {3}{4} & \frac {1}{2}, \frac {1}{2}, 1, 1 \\0, \frac {1}{4}, \frac {1}{2}, \frac {3}{4}, 1, 0 & \end {matrix} \middle | {\frac {1}{d^{2} x^{2}}} \right )}}{4 \pi ^{\frac {3}{2}} d} + \frac {c {G_{6, 6}^{2, 6}\left (\begin {matrix} - \frac {1}{2}, - \frac {1}{4}, 0, \frac {1}{4}, \frac {1}{2}, 1 & \\- \frac {1}{4}, \frac {1}{4} & - \frac {1}{2}, 0, 0, 0 \end {matrix} \middle | {\frac {e^{- 2 i \pi }}{d^{2} x^{2}}} \right )}}{4 \pi ^{\frac {3}{2}} d} \]
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Time = 0.28 (sec) , antiderivative size = 57, normalized size of antiderivative = 1.19 \[ \int \frac {a+b x+c x^2}{x^2 \sqrt {1-d x} \sqrt {1+d x}} \, dx=-b \log \left (\frac {2 \, \sqrt {-d^{2} x^{2} + 1}}{{\left | x \right |}} + \frac {2}{{\left | x \right |}}\right ) + \frac {c \arcsin \left (d x\right )}{d} - \frac {\sqrt {-d^{2} x^{2} + 1} a}{x} \]
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Leaf count of result is larger than twice the leaf count of optimal. 282 vs. \(2 (44) = 88\).
Time = 0.40 (sec) , antiderivative size = 282, normalized size of antiderivative = 5.88 \[ \int \frac {a+b x+c x^2}{x^2 \sqrt {1-d x} \sqrt {1+d x}} \, dx=-\frac {\frac {4 \, a d^{2} {\left (\frac {\sqrt {2} - \sqrt {-d x + 1}}{\sqrt {d x + 1}} - \frac {\sqrt {d x + 1}}{\sqrt {2} - \sqrt {-d x + 1}}\right )}}{{\left (\frac {\sqrt {2} - \sqrt {-d x + 1}}{\sqrt {d x + 1}} - \frac {\sqrt {d x + 1}}{\sqrt {2} - \sqrt {-d x + 1}}\right )}^{2} - 4} + b d \log \left ({\left | -\frac {\sqrt {2} - \sqrt {-d x + 1}}{\sqrt {d x + 1}} + \frac {\sqrt {d x + 1}}{\sqrt {2} - \sqrt {-d x + 1}} + 2 \right |}\right ) - b d \log \left ({\left | -\frac {\sqrt {2} - \sqrt {-d x + 1}}{\sqrt {d x + 1}} + \frac {\sqrt {d x + 1}}{\sqrt {2} - \sqrt {-d x + 1}} - 2 \right |}\right ) - {\left (\pi + 2 \, \arctan \left (\frac {\sqrt {d x + 1} {\left (\frac {{\left (\sqrt {2} - \sqrt {-d x + 1}\right )}^{2}}{d x + 1} - 1\right )}}{2 \, {\left (\sqrt {2} - \sqrt {-d x + 1}\right )}}\right )\right )} c}{d} \]
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Time = 4.08 (sec) , antiderivative size = 114, normalized size of antiderivative = 2.38 \[ \int \frac {a+b x+c x^2}{x^2 \sqrt {1-d x} \sqrt {1+d x}} \, dx=b\,\left (\ln \left (\frac {{\left (\sqrt {1-d\,x}-1\right )}^2}{{\left (\sqrt {d\,x+1}-1\right )}^2}-1\right )-\ln \left (\frac {\sqrt {1-d\,x}-1}{\sqrt {d\,x+1}-1}\right )\right )-\frac {4\,c\,\mathrm {atan}\left (\frac {d\,\left (\sqrt {1-d\,x}-1\right )}{\left (\sqrt {d\,x+1}-1\right )\,\sqrt {d^2}}\right )}{\sqrt {d^2}}-\frac {a\,\sqrt {1-d\,x}\,\sqrt {d\,x+1}}{x} \]
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